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Thermal de Broglie wavelength
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Thermal de Broglie wavelength : ウィキペディア英語版
Thermal de Broglie wavelength
In physics, the thermal de Broglie wavelength (\Lambda) is roughly the average de Broglie wavelength of the gas particles in an ideal gas at the specified temperature. We can take the average interparticle spacing in the gas to be approximately where is the volume and is the number of particles. When the thermal de Broglie wavelength is much smaller than the interparticle distance, the gas can be considered to be a classical or Maxwell–Boltzmann gas. On the other hand, when the thermal de Broglie wavelength is on the order of or larger than the interparticle distance, quantum effects will dominate and the gas must be treated as a Fermi gas or a Bose gas, depending on the nature of the gas particles. The critical temperature is the transition point between these two regimes, and at this critical temperature, the thermal wavelength will be approximately equal to the interparticle distance. That is, the quantum nature of the gas will be evident for

:
\displaystyle
\frac \le 1
\ , \
\left( \frac \right)^ \le \Lambda

i.e., when the interparticle distance is less than the thermal de Broglie wavelength;
in this case the gas will obey Bose–Einstein statistics or Fermi–Dirac statistics,
whichever is appropriate. This is for example the case for electrons in a typical metal at ''T'' = 300 K, where the electron gas obeys Fermi–Dirac statistics, or in a Bose–Einstein condensate.
On the other hand, for

:
\displaystyle
\frac \gg 1
\ , \
\left( \frac \right)^ \gg \Lambda

i.e., when the interparticle distance is much larger than the thermal de Broglie wavelength,
the gas will obey Maxwell–Boltzmann statistics. Such is the case for thermal neutrons produced by a neutron source.
==Massive Particles==

For a free ideal gas of massive particles (with no internal degrees of freedom) in equilibrium, the thermal de Broglie wavelength can be obtained through the standard de Broglie wavelength:
:\Lambda = \frac, with the substitution of the momentum (p) by the kinetic energy E_K = \frac:
:\Lambda = \frac} = \frac{\sqrt{2\pi mk_BT}},
where is the Planck constant, is the mass of a gas particle, k_B is the Boltzmann constant, and is the temperature of the gas.〔

抄文引用元・出典: フリー百科事典『 ウィキペディア(Wikipedia)
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